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Exercise 4 · Q7

Q.The speed of a motor boat and that of the current of water is 36:5. The boat goes along with the current in 5 hours 10 minutes. How much time will it take to come back?

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Downstream and upstream speeds are 36+536+5 and 36−536-5 in ratio units; for equal distance, time is inversely proportional to speed, giving a return time of 66 h 5050 min.

For a fixed distance, tup×vup=tdown×vdownt_{up}\times v_{up} = t_{down}\times v_{down}, so tup=tdown×vdownvupt_{up} = t_{down}\times \dfrac{v_{down}}{v_{up}}, with vdown=b+cv_{down}=b+c and vup=b−cv_{up}=b-c.

  1. Let boat speed b=36kb = 36k and current c=5kc = 5k (ratio 36:536:5).
  2. Downstream speed =b+c=36k+5k=41k= b+c = 36k+5k = 41k; upstream speed =b−c=36k−5k=31k= b-c = 36k-5k = 31k.
  3. Downstream time =5 h 10 min=5+1060=316= 5\text{ h }10\text{ min} = 5 + \dfrac{10}{60} = \dfrac{31}{6} h. …

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