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Exercise 9 · Q8

Q.Insert the appropriate sign of inequality: 3(50−32)‾354+224\sqrt{3}(\sqrt{50} - \sqrt{32}) \underline{\quad\quad} 3\sqrt{54} + 2\sqrt{24}

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Simplifying, the left side is 6≈2.45\sqrt6\approx2.45 and the right side is 136≈31.813\sqrt6\approx31.8, so the correct sign is <<.

Simplify each surd to the form kmk\sqrt{m} using a2b=ab\sqrt{a^2 b} = a\sqrt{b}, then compare the coefficients of the common surd.

  1. Left side 3(50−32)\sqrt3(\sqrt{50}-\sqrt{32}):
    • 50=25⋅2=52\sqrt{50} = \sqrt{25\cdot2} = 5\sqrt2, 32=16⋅2=42\sqrt{32} = \sqrt{16\cdot2} = 4\sqrt2.
    • 50−32=52−42=2\sqrt{50}-\sqrt{32} = 5\sqrt2 - 4\sqrt2 = \sqrt2.
    • 3×2=6\sqrt3 \times \sqrt2 = \sqrt6.
  2. Right side 354+2243\sqrt{54}+2\sqrt{24}:
    • 54=9⋅6=36⇒354=96\sqrt{54} = \sqrt{9\cdot6} = 3\sqrt6 \Rightarrow 3\sqrt{54} = 9\sqrt6. …

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