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Worked Examples · Example 11.1

Q.A user wants to upload a text document at the rate of 10 pages per 20 second. What will be the required data rate of the channel? (Assume that 1 page contains 1600 characters and each character is of 8 bits).

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The required data rate is 6400 bps (bits per second), calculated by converting the page rate to a character rate and then to a bit rate.

This is a straightforward data rate calculation problem — the kind you'll see in networking chapters of Class 12 Informatics Practices or Computer Science. The core idea is simple: data rate is just the amount of data transferred per unit time. You're given a rate in pages per second, and you need to convert that into bits per second.

Let's break it down step by step.

First, find the number of characters per second. The user uploads 10 pages in 20 seconds, so that's:

10 pages20 seconds=0.5 pages per second\frac{10 \text{ pages}}{20 \text{ seconds}} = 0.5 \text{ pages per second}

Each page has 1600 characters, so the character rate is:

0.5×1600=800 characters per second0.5 \times 1600 = 800 \text{ characters per second}

Now, each character is 8 bits. So the bit rate is:

800×8=6400 bits per second800 \times 8 = 6400 \text{ bits per second}

That's your answer: 6400 bps. …

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