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1.3 — Long Answer Questions

Q.Draw a knockout fixture of 13 teames.

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13 teams → 12 matches, 3 byes split as 1 in the Upper Half and 2 in the Lower Half, allotted last-of-Lower → first-of-Upper → last-of-Upper.

Step 1 — Total matches. Matches = Number of teams − 1 = 13 − 1 = 12.

Step 2 — Byes. The next power of 2 above 13 is 16, so byes = 16 − 13 = 3.

Step 3 — Halves. 13 is odd, so Upper Half = (13 + 1) / 2 = 7 teams, Lower Half = (13 − 1) / 2 = 6 teams.

Step 4 — Split the byes. With 3 (an odd number of) byes, the smaller/Upper half gets (3 − 1) / 2 = 1 bye, and the larger/Lower half gets (3 + 1) / 2 = 2 byes (this mirrors the textbook's own 11-team illustration, which splits 5 byes as 2 Upper / 3 Lower in the same way).

Step 5 — Allot the byes in order: 1st bye → last team of the Lower Half; 2nd bye → first team of the Upper Half; 3rd bye → last team of the Upper Half.

Step 6 — The fixture (teams numbered 1-13, Upper = 1-7, Lower = 8-13):

  • Teams 1 (Upper, by 2nd-bye rule) and 13 (Lower, by 1st-bye rule) and 7 (Upper, by 3rd-bye rule) get a bye straight to Round 2. …

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