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NCERT Exemplar · Q15

Q.Three compounds are given, all benzyl-type alcohols:

(a) benzyl alcohol, C6H5-CH2OH;
(b) 4-nitrobenzyl alcohol (a benzene ring bearing -CH2OH and a -NO2 group at the para position); and
(c) 4-chlorobenzyl alcohol (a benzene ring bearing -CH2OH and a -Cl group at the para position). Mark the correct increasing order of their reactivity with HBr/HCl.
(i) a < b < c
(ii) b < a < c
(iii) b < c < a
(iv) c < b < a
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Substitution of -OH by halogen from HX on a benzylic alcohol goes through a benzylic carbocation intermediate. The more stable that cation, the faster the reaction. Electron-withdrawing ring substituents (-NO2 strongly, -Cl moderately) destabilise the cation, so reactivity increases in the order b < c < a.

Concept

Benzylic alcohols react with HBr/HCl largely by an SN1 pathway: protonation of -OH, loss of water to give a resonance-stabilised benzylic carbocation, then capture by the halide. Anything that stabilises the positive charge speeds the reaction; anything that destabilises it slows the reaction.

Analysis of substituent effects

  • (b) p-nitrobenzyl alcohol: -NO2 is a strong electron-withdrawing group (-I and -M). It pulls electron density away from the electron-deficient benzylic carbon, strongly destabilising the carbocation -> slowest. …

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