NCERT Exemplar · Q7
Q.A six-carbon open-chain compound is given: CH3-CH(Cl)-CH2-CH2-CH(OH)-CH3. It carries a chlorine atom on the second carbon from one end and a hydroxyl group on the second carbon from the other end. What is its IUPAC name?
(i) 2-chloro-5-hydroxyhexane
(ii) 2-hydroxy-5-chlorohexane
(iii) 5-chlorohexan-2-ol
(iv) 2-chlorohexan-5-ol
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Start your 14-day free trial to unlock the full solution →The -OH group is the principal characteristic group and must get the lowest possible locant and the -ol suffix; chlorine is only a prefix. Numbering the six-carbon chain from the hydroxyl end puts OH at C-2 and Cl at C-5, giving the IUPAC name 5-chlorohexan-2-ol.
Concept
When an alcohol and a halogen are both present, the hydroxyl group is the principal characteristic group (suffix -ol) and the halogen (chloro) is a substituent prefix. The chain is numbered to give the principal group the lowest locant.
Steps
- Longest chain: six carbons -> parent hexane; with -OH it becomes hexanol.
- Number from the end nearer the -OH. From the -OH end: OH at C-2, Cl at C-5. From the other end: OH at C-5, Cl at C-2. Since -OH must get the lower number, choose numbering with OH at C-2. …
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