Intext Questions · 7.3
Q.Name the following compounds according to IUPAC system.
(i)
(ii)
(iv)
(v)
Sikkim CbseNCERTSubjective· 3mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →These are polyfunctional alcohols; in each, the -OH (or the pair of -OH groups, for a diol) fixes the parent and gets the lowest locant, and the halogen/alkyl/double-bond are prefixes or the '-en-' infix.
Concept
The hydroxyl group is senior, so the parent chain must contain the carbinol carbon(s) and -OH receives the lowest possible number. A double bond is shown by 'en' with its own locant; halogens and alkyl groups are alphabetised prefixes.
Step-by-step
- The carbinol carbon (-CH2OH) is C-1. Taking the four-carbon chain -CH2OH-CH-CH-CH2Cl as the parent (butan-1-ol) gives an isopropyl [1-methylethyl] group at C-2, an ethyl at C-3 and chlorine at C-4, so it is 4-chloro-3-ethyl-2-(1-methylethyl)butan-1-ol. (This is the name expected by NCERT/CBSE; note that by the strict longest-chain rule the same molecule can also be written as 3-(chloromethyl)-2-(1-methylethyl)pentan-1-ol.)
- Both -OH groups (one -OH and one -CH2OH) lie on a six-carbon chain, giving hexane-1,3-diol, with methyls at C-2 and C-5, so it is 2,5-dimethylhexane-1,3-diol. …
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