NCERT Exemplar · Q12
Q.In a series LCR circuit, the peak current is plotted against the driving angular frequency . The plot is a resonance (bell-shaped) curve: the vertical axis is marked in amperes at and , and the horizontal axis is marked in rad/s at and . Starting near zero, the current rises to a peak of about A close to rad/s and then falls back towards zero. Find the bandwidth of this resonance curve and indicate the half-power points on it.
Sikkim CbseSubjective· 2mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Bandwidth of a resonance curve is the frequency interval between the two half-power points, where the current drops to . With A the half-power level is A; the two frequencies at that level are about and rad/s, so the bandwidth is roughly rad/s.
Concept: bandwidth and half-power points
At resonance () the series LCR current is maximum, . The half-power points and are the frequencies on either side of where the power delivered is half the maximum. Since power , half power means
The bandwidth is .
Reading the curve
- The peak height is A, occurring near rad/s.
- The half-power current is A.
- Draw a horizontal line at A. It cuts the rising side of the curve at rad/s (right at the printed gridline) and the falling side at rad/s (a little short of the printed gridline). These are the two points to mark on the graph. …
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