Q.The output of a step-down transformer is measured to be 24 V when connected to a 12 W light bulb. The value of the peak current is
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Power Dissipation in Resistors
Whenever charge is driven through a resistor, electrical energy is converted into heat. The rate of this conversion is the power dissipated.
Why a Resistor Heats Up
Inside a resistor, drifting electrons repeatedly collide with the vibrating lattice ions. Each collision transfers kinetic energy to the lattice, raising its temperature. The source (battery or AC supply) continually does work to keep the current flowing, and that work reappears as heat. This is Joule heating.
The Power Formulas (DC)
The power delivered to any device carrying current I across a potential difference V is
P=VI
For an ohmic resistor V=IR, so this can be written in three equivalent forms:
P=VI=I2R=RV2
The SI unit is the watt (W), where 1 W=1 J s−1.
Which form to use depends on what is fixed:
- Series elements share the same current, so P=I2R shows the larger resistor dissipates more.
- Parallel elements share the same voltage, so P=V2/R shows the smaller resistor dissipates more.
The total heat produced in time t is Q=Pt=I2Rt — Joule's law of heating.
Power Dissipation with AC
With alternating current the instantaneous power p(t)=i2(t)R fluctuates, but a resistor still only dissipates energy (it never returns any). The average power over a cycle is written with root-mean-square values:
Pavg=Irms2R=RVrms2=VrmsIrms
where for a sinusoid Irms=Im/2 and Vrms=Vm/2. This is precisely why rms values are defined: an AC of rms value Irms heats a resistor at the same average rate as a steady DC of value Irms.
A pure resistor has power factor 1 — voltage and current are in phase, so all the power supplied is dissipated. In inductors and capacitors, by contrast, the average dissipated power is zero; energy is only stored and returned.
Worked Example
A 100 Ω resistor carries a current of 0.5 A. …
Why this formula?
Power Dissipation in Resistors — Why the Formula Holds
Let's build this from first principles. The goal is to understand why a resistor dissipates power as heat, and how the formula P=I2R (and its equivalents) arise naturally.
1. What is "Power" in an Electrical Circuit?
Power is the rate of energy transfer — how much energy is converted from one form to another per unit time.
- In a resistor, electrical energy is converted into heat (thermal energy).
- The fundamental definition of electrical power is:
P=V⋅I
where:
- P = power (watts, W)
- V = voltage across the component (volts, V)
- I = current through the component (amperes, A)
Why this definition?
Voltage is energy per unit charge (V=qW), and current is charge per unit time (I=tq). Multiplying them gives energy per unit time — exactly power.
2. How Does a Resistor Behave? — Ohm's Law
A resistor obeys Ohm's Law:
V=I⋅R
where R is resistance (ohms, Ω). This is an empirical law — it describes how real resistors behave: the voltage across them is proportional to the current through them.
3. Deriving the Power Dissipation Formulas
We start with P=VI and substitute Ohm's Law in two ways.
Case A: Express power in terms of I and R
Replace V with IR:
P=(IR)⋅I=I2R
Interpretation:
- For a fixed resistance, power grows with the square of current.
- Doubling current quadruples the heat generated — this is why high currents cause wires to overheat.
Case B: Express power in terms of V and R
Replace I with RV:
P=V⋅(RV)=RV2
Interpretation:
- For a fixed voltage, power is inversely proportional to resistance.
- A low-resistance resistor (like a short circuit) dissipates huge power at a given voltage — that's why short circuits are dangerous.
4. The Physical "Why" — Energy Conversion at the Atomic Level
Why does this energy turn into heat?
- Electrons moving through a resistor collide with the atoms of the material.
- Each collision transfers kinetic energy from the electron to the atom, making the atom vibrate more — i.e., heating up the resistor.
- The rate at which this energy is lost by the electrons (and gained by the lattice) is exactly P=I2R.
Key insight:
The I2 term appears because:
- More current = more electrons per second. …
Concept: Power Dissipation in Resistors — the bulb's rated power and voltage give its resistance, and the transformer output is RMS voltage.
- The bulb operates at its rated power when connected to the transformer's RMS output. Using P=RVrms2, the resistance is:
R=PVrms2=12242=12576=48 Ω.
- The RMS current through the bulb is: Irms=RVrms=4824=0.5 A. …
The transformer output 24 V is an rms value. Find the rms current from P=VI, then scale by 2: peak current ≈0.71 A.
The rated bulb power and the output voltage are rms quantities, so
Irms=VrmsP=24 V12 W=0.5 A.
The peak current is
I0=2Irms=2(0.5)=21≈0.707 A. …
Method: Relating Rated Power, RMS Values, and Peak Values for an AC Load
Use this method whenever a device's rated power and its rms operating voltage are given, and the question asks for a peak (rather than rms) current or voltage.
Steps
Step 1: Recognise that stated AC voltages and rated powers are rms quantities unless stated otherwise.
A transformer's quoted output voltage and a bulb's rated wattage are both rms/average quantities by convention — this is the assumption that lets you connect them with the simple power relation below.
Step 2: Use P=VrmsIrms to extract the rms current directly.
Irms=VrmsP
This works directly for a resistive load (like a bulb) without needing to separately find its resistance first, though computing R=Vrms2/P as an intermediate step is an equally valid route to the same answer.
Step 3: Convert the rms current to peak current.
I0=2Irms …
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