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Question 32 of 48

Q.Sum of the binomial coefficients is :

(a) 2n2n
(b) 2n2^n
(c) n+17n+17
(d) n2n^2
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Commerce Board 2023MCQ· 1mImportance★★★★★
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Setting x=1x = 1 in (1+x)n(1+x)^n gives (n0)+(n1)+⋯+(nn)=2n\binom{n}{0}+\binom{n}{1}+\dots+\binom{n}{n} = 2^n, so the answer is option (b).

The binomial theorem states

(1+x)n=(n0)+(n1)x+(n2)x2+⋯+(nn)xn.(1+x)^n = \binom{n}{0} + \binom{n}{1}x + \binom{n}{2}x^2 + \dots + \binom{n}{n}x^n.

Substitute x=1x = 1:

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