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Worked Examples · Example 2

Q.The demand function for a commodity is p=100−2xp = 100 - 2x, where pp is the price per unit and xx is the quantity demanded. Find the total revenue function and the marginal revenue when x=10x=10.

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✓ Free question

Step 1 — Form the total revenue function. R(x)=x⋅p=x(100−2x)=100x−2x2R(x) = x \cdot p = x(100-2x) = 100x-2x^2.

Step 2 — Differentiate to get marginal revenue. MR(x)=R′(x)=100−4xMR(x) = R'(x) = 100-4x.

Step 3 — Evaluate at x=10x=10. MR(10)=100−4(10)=100−40=60MR(10) = 100-4(10) = 100-40=60.

Independent check. Compute R(10)R(10) and R(11)R(11) directly and compare their difference to the marginal revenue: R(10)=100(10)−2(100)=1000−200=800R(10)=100(10)-2(100)=1000-200=800; R(11)=100(11)−2(121)=1100−242=858R(11)=100(11)-2(121)=1100-242=858. The actual increase, 858−800=58858-800=58, is close to the calculus estimate of MR(10)=60MR(10)=60 — the small gap is expected, since MR is the instantaneous rate of change at x=10x=10, while 5858 is the actual change over one whole extra unit; the two agree closely but not exactly, exactly as calculus predicts for a discrete step.

✓Final answer

R(x)=100x−2x2R(x) = 100x-2x^2; the marginal revenue at x=10x=10 is 6060.

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