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Worked Examples · Example 4

Q.Using the same advertising and sales data as Worked Example 1 (xˉ=3,yˉ=4\bar x=3,\bar y=4, ∑(x−xˉ)(y−yˉ)=6\sum(x-\bar x)(y-\bar y)=6, ∑(x−xˉ)2=10\sum(x-\bar x)^2=10, ∑(y−yˉ)2=6\sum(y-\bar y)^2=6), find the two regression coefficients byxb_{yx} and bxyb_{xy}, and verify the relation r2=byx⋅bxyr^2=b_{yx}\cdot b_{xy}.

Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
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Step 1 — Apply the two regression-coefficient formulas, reusing the sums from Worked Example 1.

byx=∑(x−xˉ)(y−yˉ)∑(x−xˉ)2=610=0.6b_{yx} = \dfrac{\sum(x-\bar x)(y-\bar y)}{\sum(x-\bar x)^2} = \dfrac{6}{10} = 0.6

bxy=∑(x−xˉ)(y−yˉ)∑(y−yˉ)2=66=1.0b_{xy} = \dfrac{\sum(x-\bar x)(y-\bar y)}{\sum(y-\bar y)^2} = \dfrac{6}{6} = 1.0

Step 2 — Verify r2=byx⋅bxyr^2=b_{yx}\cdot b_{xy}. byx×bxy=0.6×1.0=0.6b_{yx}\times b_{xy} = 0.6\times1.0=0.6. From Worked Example 1, r=6/60r=6/\sqrt{60} exactly, so r2=36/60=0.6r^2 = 36/60=0.6 — matches byxbxyb_{yx}b_{xy} exactly (not just approximately, since both were computed from exact fractions before rounding). …

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