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Business Mathematics and Statistics · Ch 8 — Descriptive Statistics and Probability

Addition Theorem of Probability

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Addition Theorem of Probability

A frequent business question involves the probability that one event OR another occurs — will a customer buy product A or product B, will a machine fail due to fault X or fault Y. The addition theorem answers exactly this, for two events AA and BB defined on the same sample space:

Note

Addition Theorem (General Form)

P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)

The subtraction of P(A∩B)P(A\cap B) exists precisely because, when AA and BB overlap (share some common outcomes), simply adding P(A)P(A) and P(B)P(B) would double-count every outcome that lies in both.

Mutually exclusive events are events that cannot occur together — they share no common outcome at all, so P(A∩B)=0P(A\cap B)=0, and the formula simplifies:

Note

Addition Theorem for Mutually Exclusive Events

P(A∪B)=P(A)+P(B)(only when A∩B=∅)P(A \cup B) = P(A) + P(B) \qquad \text{(only when } A \cap B = \varnothing\text{)}

A classic example of mutually exclusive events: rolling a single die and getting 'an even number' versus 'an odd number' — no outcome is both, so the two probabilities can simply be added. By contrast, 'an even number' and 'a number greater than 3' on a die do overlap (both include 4 and 6), so the general (subtract-the-overlap) form must be used instead. …

Definition 11Addition Theorem of Probability

P(A∪B)=P(A)+P(B)−P(A∩B)P(A\cup B) = P(A)+P(B)-P(A\cap B), the probability that AA or BB (or both) occurs; the overlap P(A∩B)P(A\cap B) is subtracted to …

Definition 12Mutually Exclusive Events

Events with no outcome in common (A∩B=∅A\cap B=\varnothing); for these, P(A∪B)=P(A)+P(B)P(A\cup B)=P(A)+P(B), since there is no …