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Worked Examples · Example 5

Q.Compare the graphs of y=2xy=2^x and y=log⁡2xy=\log_2 x, stating the domain, range, and the relationship between the two graphs.

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Step 1 — y=2xy=2^x. Any real number can be used as an exponent, so the domain is R\mathbb{R}. Since 2x>02^x>0 for every real xx (a positive base raised to any power stays positive) and 2x2^x takes every positive value as xx ranges over R\mathbb{R}, the range is (0,∞)(0,\infty). The graph passes through (0,1)(0,1) (since 20=12^0=1), rises steeply for large xx, and approaches (but never reaches) the xx-axis as x→−∞x\to-\infty.

Step 2 — y=log⁡2xy=\log_2x. By definition, log⁡2x\log_2x asks 'to what power must 22 be raised to give xx?', which only makes sense for x>0x>0 — domain (0,∞)(0,\infty). As xx ranges over all positive numbers, the required power ranges over all real numbers — range R\mathbb{R}. The graph passes through (1,0)(1,0) (since 20=12^0=1), rises slowly, and has a vertical asymptote at x=0x=0. …

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