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Exercises · Q5

Q.Determine the sign of cos⁡200∘\cos200^\circ and tan⁡320∘\tan320^\circ, without using a calculator.

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Step 1 — locate 200∘200^\circ. Since 180∘<200∘<270∘180^\circ<200^\circ<270^\circ, this angle is in the third quadrant. By the All–Sin–Tan–Cos rule, only tan and cot are positive in QIII, so cosine is negative there: cos⁡200∘<0\cos200^\circ<0.

Step 2 — locate 320∘320^\circ. Since 270∘<320∘<360∘270^\circ<320^\circ<360^\circ, this angle is in the fourth quadrant, where only cos and sec are positive, so tangent is negative: tan⁡320∘<0\tan320^\circ<0.

Check (independent route — write each as 180∘180^\circ or 360∘360^\circ plus/minus a reference angle and use the reduction formula). 200∘=180∘+20∘200^\circ=180^\circ+20^\circ, so cos⁡200∘=cos⁡(180∘+20∘)=−cos⁡20∘\cos200^\circ=\cos(180^\circ+20^\circ)=-\cos20^\circ, and since cos⁡20∘\cos20^\circ is a small positive number, −cos⁡20∘-\cos20^\circ is negative — confirming cos⁡200∘<0\cos200^\circ<0. Similarly 320∘=360∘−40∘320^\circ=360^\circ-40^\circ, so tan⁡320∘=tan⁡(360∘−40∘)=−tan⁡40∘\tan320^\circ=\tan(360^\circ-40^\circ)=-\tan40^\circ, which is negative — confirming tan⁡320∘<0\tan320^\circ<0.

✓Final answer

cos⁡200∘\cos200^\circ is negative; tan⁡320∘\tan320^\circ is negative

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