Skip to content
Worked Examples · Example 4

Q.A monopolist selling in two separate markets, A and B, has a constant Marginal Cost of Rs. 10. The demand functions are PA=50−QAP_{A}=50-Q_{A} in Market A and PB=40−2QBP_{B}=40-2Q_{B} in Market B. Find the profit-maximising price and quantity in each market, verify that MRA=MRB=MCMR_A=MR_B=MC, and calculate total profit.

Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
28% · 10/36 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Market A: TRA=PA×QA=(50−QA)QA=50QA−QA2TR_A=P_A\times Q_A=(50-Q_A)Q_A=50Q_A-Q_A^{2}, so MRA=50−2QAMR_A=50-2Q_A. Setting MRA=MC=10MR_A=MC=10:

50−2QA=10⇒QA=20,PA=50−20=Rs. 3050-2Q_A=10 \Rightarrow Q_A=20,\qquad P_A=50-20=Rs.\,30

Market B: TRB=PB×QB=(40−2QB)QB=40QB−2QB2TR_B=P_B\times Q_B=(40-2Q_B)Q_B=40Q_B-2Q_B^{2}, so MRB=40−4QBMR_B=40-4Q_B. Setting MRB=MC=10MR_B=MC=10:

40−4QB=10⇒QB=7.5,PB=40−2(7.5)=Rs. 2540-4Q_B=10 \Rightarrow Q_B=7.5,\qquad P_B=40-2(7.5)=Rs.\,25

Verification of the price-discrimination rule: MRA=50−2(20)=10MR_A=50-2(20)=10 and MRB=40−4(7.5)=10MR_B=40-4(7.5)=10 — both equal Rs. 10, which is also equal to MC, exactly satisfying MRA=MRB=MCMR_A=MR_B=MC.

Total profit:

Profit=(PA−MC)QA+(PB−MC)QB=(30−10)(20)+(25−10)(7.5)=400+112.5=Rs. 512.5\text{Profit}=(P_A-MC)Q_A+(P_B-MC)Q_B=(30-10)(20)+(25-10)(7.5)=400+112.5=Rs.\,512.5 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.