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Choose the Best Answer · Q25

Q.A sample of 0.5 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M H2SO4. The remaining acid after neutralisation by ammonia consumed 80 mL of 0.5 M NaOH. The percentage of nitrogen in the organic compound is

a) 14%
b) 28%
c) 42%
d) 56%
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Step 1. H2SO4 is diprotic, so its normality is twice its molarity: 0.5 M H2SO4 = 1.0 N. Initial acid taken = 50 mL x 1.0 N = 50 milliequivalents (meq).

Step 2. NaOH is monobasic, so 0.5 M NaOH = 0.5 N. The unreacted (excess) acid, found by back-titration, consumed 80 mL x 0.5 N = 40 meq of NaOH, meaning 40 meq of acid was left UNREACTED by the ammonia.

Step 3. Acid that actually reacted with the evolved ammonia = 50 - 40 = 10 meq. …

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