$\displaystyle\int \left(\dfrac{x-1}{x+1}\right) dx$ is: (a) $x - 2\log(x+1) + c$ (b) $\log(x+1) + c$ (c) $x + 2\log(x-1) + c$ (d) $\log(x-1) + c$

∫ ((x-1)/(x+1)) dx is: (a) x - 2log(x+1) + c (b) l – Class 11 Mathematics

Question 101 of 129

\displaystyle\int \left(\dfrac{x-1}{x+1}\right) dx

(a)

x - 2\log(x+1) + c

(b)

\log(x+1) + c

(c)

x + 2\log(x-1) + c

(d)

\log(x-1) + c

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2018MCQ· 1mImportance★★★★★

78% · 101/129 Questions

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Splitting $\dfrac{x-1}{x+1} = 1 - \dfrac{2}{x+1}$ and integrating term by term gives $x-2\log(x+1)+c$ .

$\dfrac{x-1}{x+1} = \dfrac{(x+1)-2}{x+1} = 1 - \dfrac{2}{x+1}$

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