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Question 125 of 129

Q.∫23x+5 dx\displaystyle\int 2^{3x+5}\,dx is:

(a) 23x+52log⁡3+c\dfrac{2^{3x+5}}{2\log 3} + c
(b) 3(23x+5)log⁡2+c\dfrac{3(2^{3x+5})}{\log 2} + c
(c) 23x+53log⁡2+c\dfrac{2^{3x+5}}{3\log 2} + c
(d) 23x+52log⁡(3x+5)+c\dfrac{2^{3x+5}}{2\log(3x+5)} + c
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2025MCQ· 1mImportance★★★★★
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This is a direct application of the standard exponential-integral formula.

Recall ∫axdx=axlog⁡a+c\displaystyle\int a^{x}dx=\dfrac{a^x}{\log a}+c. For a linear exponent 3x+53x+5, let u=3x+5u=3x+5, du=3 dxdu=3\,dx: …

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