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Exercise 7.1 · Q3

Q.Determine the value of x+yx+y if
[!FORMULA] (2x+y4x5x−74x)=(77y−13yx+6)\begin{pmatrix} 2x+y & 4x \\ 5x-7 & 4x\end{pmatrix} = \begin{pmatrix} 7 & 7y-13 \\ y & x+6\end{pmatrix}

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Comparing corresponding entries of the two equal matrices gives four equations in x,yx,y; the simplest one solves for xx immediately, and back-substitution gives yy.

Step 1. Write the four entry-equations.

(1,1): 2x+y=7(1,1):\ 2x+y=7

(1,2): 4x=7y−13(1,2):\ 4x=7y-13

(2,1): 5x−7=y(2,1):\ 5x-7=y

(2,2): 4x=x+6(2,2):\ 4x=x+6

Step 2. Solve the (2,2)(2,2) equation for xx. 4x=x+6⇒3x=6⇒x=24x=x+6\Rightarrow 3x=6\Rightarrow x=2.

Step 3. Substitute x=2x=2 into (1,1)(1,1) to get yy. 2(2)+y=7⇒4+y=7⇒y=32(2)+y=7\Rightarrow 4+y=7\Rightarrow y=3.

Step 4. Verify with the remaining equations. (1,2):4(2)=8(1,2):4(2)=8 and 7(3)−13=21−13=87(3)-13=21-13=8 ✓. (2,1):5(2)−7=3=y(2,1):5(2)-7=3=y ✓. Both check out, confirming x=2,y=3x=2,y=3.

Step 5. Compute the required sum. x+y=2+3=5x+y=2+3=5.

✓Final answer

x+y=5x+y=\boxed{5}.

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