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Exercise 7.1 · Q5

Q.If A=(1a01)A=\begin{pmatrix} 1 & a \\ 0 & 1\end{pmatrix}, then compute A4A^4.

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AA is an upper-triangular matrix with 11's on the diagonal, so its powers follow the simple pattern An=(1na01)A^n=\begin{pmatrix}1&na\\0&1\end{pmatrix}; we verify this by direct multiplication up to A4A^4.

Step 1. Compute A2=A⋅AA^2=A\cdot A.

A2=(1a01)(1a01)=(1⋅1+a⋅01⋅a+a⋅10⋅1+1⋅00⋅a+1⋅1)=(12a01)A^2=\begin{pmatrix}1&a\\0&1\end{pmatrix}\begin{pmatrix}1&a\\0&1\end{pmatrix}=\begin{pmatrix}1\cdot1+a\cdot0 & 1\cdot a+a\cdot1\\ 0\cdot1+1\cdot0 & 0\cdot a+1\cdot1\end{pmatrix}=\begin{pmatrix}1&2a\\0&1\end{pmatrix}

Step 2. Compute A4=A2⋅A2A^4=A^2\cdot A^2.

A4=(12a01)(12a01)=(1⋅1+2a⋅01⋅2a+2a⋅10⋅1+1⋅00⋅2a+1⋅1)=(14a01)A^4=\begin{pmatrix}1&2a\\0&1\end{pmatrix}\begin{pmatrix}1&2a\\0&1\end{pmatrix}=\begin{pmatrix}1\cdot1+2a\cdot0 & 1\cdot2a+2a\cdot1\\ 0\cdot1+1\cdot0 & 0\cdot2a+1\cdot1\end{pmatrix}=\begin{pmatrix}1&4a\\0&1\end{pmatrix} …

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