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Exercise 7.2 · Q12

Q.If a,b,ca, b, c are all positive, and are pthp^{\text{th}}, qthq^{\text{th}} and rthr^{\text{th}} terms of a G.P., show that ∣log⁡ap1log⁡bq1log⁡cr1∣=0.\begin{vmatrix} \log a & p & 1 \\ \log b & q & 1 \\ \log c & r & 1 \end{vmatrix} = 0.

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Concept understanding — Properties of Determinants

These properties let a determinant be simplified — often to 00 — without full expansion.

  1. Transpose invariance: ∣AT∣=∣A∣|A^T|=|A| (row-wise and column-wise expansion agree).
  2. Row/column swap: interchanging any two rows (or columns) changes the sign of the determinant, leaving its absolute value unchanged. More generally, nn interchanges multiply the determinant by (−1)n(-1)^n.
  3. Identical rows/columns: if two rows (or columns) are identical, ∣A∣=0|A|=0. (Proof idea: swapping the identical rows leaves the matrix unchanged but must flip the sign by Property 2, forcing ∣A∣=−∣A∣|A|=-|A|, so ∣A∣=0|A|=0.)
  4. Proportional rows/columns: if one row (or column) is a scalar multiple of another, ∣A∣=0|A|=0; in particular, an all-zero row/column forces ∣A∣=0|A|=0.
  5. Scalar factor: multiplying every entry of one row (or column) by a scalar kk multiplies the whole determinant by kk. Consequently ∣kA∣=kn∣A∣|kA| = k^n|A| for an n×nn\times n matrix AA (every one of the nn rows is scaled by kk).
  6. Sum splitting: if every entry of one row (or column) is a sum of two terms, the determinant splits as the sum of two determinants (one with each term in that row/column, all other rows/columns unchanged).
  7. Row/column operations: adding to any row (column) a scalar multiple of another row (column) — e.g. Ri→Ri+pRj+qRkR_i \to R_i + pR_j + qR_k — leaves the determinant unchanged. This is the workhorse trick used to create zeros before expanding. …

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