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Exercise 1.4 · Q7

Q.From the curve y=∣x∣y=|x|, draw

(i) y=∣x−1∣+1y=|x-1|+1
(ii) y=∣x+1∣−1y=|x+1|-1
(iii) y=∣x+2∣−3y=|x+2|-3.
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Step 1 (i) y=∣x−1∣+1y=|x-1|+1. This is f(x−1)+1f(x-1)+1: shift RIGHT by 1 (since x−1x-1 inside), then UP by 1. The V-vertex moves from (0,0)(0,0) to (1,1)(1,1).

Step 2 (ii) y=∣x+1∣−1y=|x+1|-1. This is f(x+1)−1f(x+1)-1: shift LEFT by 1, then DOWN by 1. Vertex moves from (0,0)(0,0) to (−1,−1)(-1,-1).

Step 3 (iii) y=∣x+2∣−3y=|x+2|-3. This is f(x+2)−3f(x+2)-3: shift LEFT by 2, then DOWN by 3. Vertex moves from (0,0)(0,0) to (−2,−3)(-2,-3). …

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