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Exercise 3.1 · Q12

Q.Eliminate θ\theta from the equations asec⁡θ−ctan⁡θ=ba\sec\theta - c\tan\theta = b and bsec⁡θ+dtan⁡θ=cb\sec\theta + d\tan\theta = c.

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Treat the two given equations as a linear system in the unknowns sec⁡θ\sec\theta and tan⁡θ\tan\theta, solve for each by elimination, and substitute both into the Pythagorean identity sec⁡2θ−tan⁡2θ=1\sec^2\theta-\tan^2\theta=1 to eliminate θ\theta entirely.

Step 1. Write the system in standard form.

asec⁡θ−ctan⁡θ=b...(I),bsec⁡θ+dtan⁡θ=c...(II).a\sec\theta - c\tan\theta = b \quad \text{...(I)}, \qquad b\sec\theta + d\tan\theta = c \quad \text{...(II)}.

Step 2. Eliminate tan⁡θ\tan\theta to solve for sec⁡θ\sec\theta. Multiply (I) by dd and (II) by cc, then add:

adsec⁡θ−cdtan⁡θ=bd,bcsec⁡θ+cdtan⁡θ=c2ad\sec\theta - cd\tan\theta = bd, \qquad bc\sec\theta + cd\tan\theta = c^2

⇒(ad+bc)sec⁡θ=bd+c2 ⇒ sec⁡θ=bd+c2ad+bc.\Rightarrow (ad+bc)\sec\theta = bd+c^2 \ \Rightarrow \ \sec\theta = \frac{bd+c^2}{ad+bc}.

Step 3. Eliminate sec⁡θ\sec\theta to solve for tan⁡θ\tan\theta. Multiply (I) by bb and (II) by aa:

absec⁡θ−bctan⁡θ=b2,absec⁡θ+adtan⁡θ=acab\sec\theta - bc\tan\theta = b^2, \qquad ab\sec\theta + ad\tan\theta = ac

Subtracting the first from the second: …

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