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Exercise 3.2 · Q11

Q.A circular metallic plate of radius 88 cm and thickness 66 mm is melted and molded into a pie (a sector of the circle with thickness) of radius 1616 cm and thickness 44 mm. Find the angle of the sector.

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Melting and remoulding preserves volume, so the volume of the original full circular plate must equal the volume of the new sector-shaped (pie) solid; setting these equal and solving for θ\theta gives the sector's angle.

Step 1. Compute the volume of the original plate. A full circular plate of radius r1=8r_1=8 cm and thickness t1=6 mm=0.6t_1=6\ \text{mm}=0.6 cm has volume

V1=πr12t1=π×82×0.6=38.4π cm3.V_1=\pi r_1^2 t_1 = \pi\times8^2\times0.6=38.4\pi\ \text{cm}^3.

Step 2. Compute the volume of the new sector-shaped solid. A "pie" of radius r2=16r_2=16 cm, central angle θ\theta (radians), thickness t2=4 mm=0.4t_2=4\ \text{mm}=0.4 cm is a sector (area 12r22θ\tfrac12r_2^2\theta) extruded to that thickness:

V2=12r22θ t2=12×162×θ×0.4=12×256×0.4×θ=51.2 θ cm3.V_2=\frac12 r_2^2\theta\, t_2=\frac12\times16^2\times\theta\times0.4=\frac12\times256\times0.4\times\theta=51.2\,\theta\ \text{cm}^3. …

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