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Exercise 8.5 · Q1

Q.The value of AB⃗+BC⃗+DA⃗+CD⃗\vec{AB}+\vec{BC}+\vec{DA}+\vec{CD} is

(1) AD⃗\vec{AD}
(2) CA⃗\vec{CA}
(3) 0⃗\vec 0
(4) −AD⃗-\vec{AD}
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Concept understanding — Algebra of Vectors

Addition — two equivalent pictures.

  • Triangle law: if a⃗=A1B1⃗\vec a=\vec{A_1B_1} and b⃗=B1B2⃗\vec b=\vec{B_1B_2} (the tail of b⃗\vec b placed at the tip of a⃗\vec a), then a⃗+b⃗\vec a+\vec b is the third side A1B2⃗\vec{A_1B_2}, taken from the start of a⃗\vec a to the end of b⃗\vec b. In words: if two vectors are represented, in magnitude and direction, by two sides of a triangle taken in order, their sum is the third side taken in the reverse order.
  • Parallelogram law: if a⃗=OA⃗\vec a=\vec{OA} and b⃗=OB⃗\vec b=\vec{OB} share the initial point OO, complete the parallelogram OACBOACB; the diagonal OC⃗\vec{OC} through OO is a⃗+b⃗\vec a+\vec b.

Both laws describe the same sum — the triangle law is just the parallelogram law applied to half of the parallelogram.

Key results proved from the triangle law:

  • If a⃗,b⃗,c⃗\vec a,\vec b,\vec c are the three sides of a triangle taken in order (tip to tail, returning to the start), a⃗+b⃗+c⃗=0⃗\vec a+\vec b+\vec c=\vec 0.
  • Vector addition is associative: (a⃗+b⃗)+c⃗=a⃗+(b⃗+c⃗)(\vec a+\vec b)+\vec c=\vec a+(\vec b+\vec c).
  • a⃗+0⃗=0⃗+a⃗=a⃗\vec a+\vec 0=\vec 0+\vec a=\vec a for every a⃗\vec a.
  • a⃗+(−a⃗)=0⃗\vec a+(-\vec a)=\vec 0, where −a⃗-\vec a (the reverse of a⃗\vec a) has the same magnitude as a⃗\vec a but the opposite direction; if a⃗=AB⃗\vec a=\vec{AB} then −a⃗=BA⃗-\vec a=\vec{BA}.
  • Vector addition is commutative: a⃗+b⃗=b⃗+a⃗\vec a+\vec b=\vec b+\vec a (proved by the parallelogram, since both diagonals lead to the same point CC).
  • Polygon law: for any chain of vectors placed tip to tail, OA⃗+AB⃗+BC⃗+CD⃗+DE⃗=OE⃗\vec{OA}+\vec{AB}+\vec{BC}+\vec{CD}+\vec{DE}=\vec{OE} — the sum is the single vector from the very first tail to the very last tip.

Subtraction. a⃗−b⃗\vec a-\vec b means a⃗+(−b⃗)\vec a+(-\vec b). Geometrically, if a⃗=OA⃗\vec a=\vec{OA} and b⃗=OB⃗\vec b=\vec{OB} are adjacent sides of parallelogram OACBOACB, the diagonal OC⃗=a⃗+b⃗\vec{OC}=\vec a+\vec b while the other diagonal BA⃗=a⃗−b⃗\vec{BA}=\vec a-\vec b.

Scalar multiplication. For a scalar mm, ma⃗m\vec a has magnitude ∣m∣ ∣a⃗∣|m|\,|\vec a|; it points the same way as a⃗\vec a when m>0m>0 and the opposite way when m<0m<0, and 0a⃗=0⃗0\vec a=\vec 0. Two vectors a⃗,b⃗\vec a,\vec b are parallel iff a⃗=λb⃗\vec a=\lambda\vec b for some scalar λ\lambda (λ>0\lambda>0: same direction; λ<0\lambda<0: opposite direction). Scalar multiplication distributes over both vector addition and scalar addition: m(a⃗+b⃗)=ma⃗+mb⃗m(\vec a+\vec b)=m\vec a+m\vec b and (m+n)a⃗=ma⃗+na⃗(m+n)\vec a=m\vec a+n\vec a, and (mn)a⃗=m(na⃗)(mn)\vec a=m(n\vec a).

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