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Physics · Ch 6 — Gravitation

Energy of an Orbiting Satellite

6.4.2

Energy of an Orbiting Satellite

A satellite's total mechanical energy is the sum of its kinetic energy and its gravitational potential energy, and this sum always comes out negative -- which is the mathematical statement that the satellite is permanently bound to the Earth.

Derivation. The potential energy of a satellite of mass MsM_s at height hh is U=−GMsMeRe+hU=-\dfrac{GM_sM_e}{R_e+h} (Eq. 6.63). Its kinetic energy uses the orbital speed found earlier, v=GMe/(Re+h)v=\sqrt{GM_e/(R_e+h)}:

K.E.=12Msv2=12GMsMeRe+h.(6.64, 6.65)K.E.=\frac{1}{2}M_sv^2=\frac{1}{2}\frac{GM_sM_e}{R_e+h}. \qquad (6.64,\,6.65)

Adding the two,

E=12GMsMeRe+h−GMsMeRe+h=−12GMsMeRe+h.(6.66)E=\frac{1}{2}\frac{GM_sM_e}{R_e+h}-\frac{GM_sM_e}{R_e+h}=-\frac{1}{2}\frac{GM_sM_e}{R_e+h}. \qquad (6.66)

The negative sign means the satellite is bound to the Earth and cannot spontaneously escape. As h→∞h\to\infty, E→0E\to0: physically, a satellite pushed out to an infinite distance would be completely free of Earth's gravitational influence, no longer bound to it at all. …