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Physics · Ch 6 — Gravitation

Escape Speed and Orbital Speed

6.4

Escape Speed and Orbital Speed

Earth's atmosphere is mostly nitrogen and oxygen, even though hydrogen and helium are by far the most abundant elements in the universe. The reason is escape speed: light gas molecules like hydrogen and helium routinely reach speeds fast enough to permanently leave Earth's gravitational pull, while the heavier nitrogen and oxygen molecules almost never do.

Defining escape speed. It is the minimum speed an object needs, launched from the Earth's surface, to escape Earth's gravitational pull for good and never fall back. Consider a mass MM launched from the surface with initial speed viv_i; its initial total energy (kinetic plus gravitational potential) is

Ei=12Mvi2−GMMeRe.(6.53)E_i=\frac{1}{2}Mv_i^2-\frac{GMM_e}{R_e}. \qquad (6.53)

For the minimum possible launch speed, the object should just barely reach an infinite distance with zero leftover kinetic energy, i.e. Ef=0E_f = 0 (since U→0U\to0 as r→∞r\to\infty too). By conservation of energy, Ei=Ef=0E_i=E_f=0, so setting vi=vev_i=v_e (the escape speed) gives

12Mve2−GMMeRe=0  ⇒  ve=2GMeRe.(6.53-6.55)\frac{1}{2}Mv_e^2-\frac{GMM_e}{R_e}=0 \;\Rightarrow\; v_e=\sqrt{\frac{2GM_e}{R_e}}. \qquad (6.53\text{-}6.55)

Using g=GMe/Re2g=GM_e/R_e^2, this simplifies neatly to

ve=2gRe.(6.56)v_e=\sqrt{2gR_e}. \qquad (6.56) …

Figure 6.19Escape speed is independent of launch direction

What this figure shows. The Earth is shown with several arrows drawn from the same launch point, pointing in different directions -- straight up, at an angle, and nearly sideways (tangential) -- to illustrate that the minimum speed needed to escape Earth's gravity for good is exactly the same number regardless of which of these directions the object is thrown in, since escape speed comes purely from energy conservation and not from the direction …