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Worked Examples · Example 2

Q.For the same transportation problem in Worked Example 1, find the initial basic feasible solution using the Least Cost (Matrix Minima) Method and compare the total cost with the North-West Corner Method.

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Using the same cost matrix and supply/demand as Worked Example 1:

  1. Lowest cost in the table is 4 at (O3,D1)(O_3,D_1): allocate min⁡(20,25)=20\min(20,25)=20; O3O_3 exhausted, D1D_1 has 5 left.
  2. Next lowest is 6 at (O1,D1)(O_1,D_1): allocate min⁡(30,5)=5\min(30,5)=5; D1D_1 exhausted, O1O_1 has 25 left.
  3. Next lowest is 8 at (O1,D2)(O_1,D_2): allocate min⁡(25,35)=25\min(25,35)=25; O1O_1 exhausted, D2D_2 has 10 left.
  4. Only the O2O_2 row remains against D2D_2 (10 left) and D3D_3 (40); the lower cost is 11 at (O2,D2)(O_2,D_2): allocate min⁡(50,10)=10\min(50,10)=10; D2D_2 exhausted, O2O_2 has 40 left.
  5. Final cell (O2,D3)(O_2,D_3): allocate min⁡(40,40)=40\min(40,40)=40.

Allocation table:

D1D_1D2D_2D3D_3Row total
O1O_1525—30
O2O_2—104050
O3O_320——20
Column total253540100

Row totals and column totals match the supplies and demands exactly; 5 occupied cells =m+n−1=m+n-1.

Total cost:

Z=20(4)+5(6)+25(8)+10(11)+40(11)=80+30+200+110+440=860Z=20(4)+5(6)+25(8)+10(11)+40(11)=80+30+200+110+440=860

Compared with Worked Example 1's NWC cost of ₹980, the Least Cost Method is ₹120 cheaper on the identical cost matrix.

✓Final answer

Total transportation cost by LCM = ₹860, which is ₹120 less than the ₹980 found by NWC

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