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Choose the Best Answer · Q5

Q.CH2=CH2, treated with

(i) O3 then
(ii) Zn/H2O, gives X; X, treated with NH3, gives Y. 'Y' is a) Formaldehyde b) di-acetone ammonia c) hexamethylene tetraamine d) oxime
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Step 1. CH2=CH2 (ethylene), treated with O3 then Zn/H2O (reductive ozonolysis), cleaves at the double bond: since BOTH alkene carbons carry two hydrogens and no other substituent, both become formaldehyde -- X = 2 HCHO (formaldehyde).

Step 2. Formaldehyde is the ONE aldehyde that reacts with ammonia in a distinctive 6:4 stoichiometry rather than forming a simple aldimine (which is how every OTHER aliphatic aldehyde reacts with NH3, Section 12.5.A.5).

Step 3. 6 HCHO + 4 NH3 gives (CH2)6N4 + 6 H2O -- the cage-like product (CH2)6N4 is hexamethylenetetramine, also known by its common name urotropine. …

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