Skip to content
Question 40 of 66

Q.Which of the following compound is optically active ?

(a) CH3CH2COOHCH_3CH_2COOH
(b) HOOC−CH2−COOHHOOC-CH_2-COOH
(c) CH3CH(OH)COOHCH_3CH(OH)COOH
(d) Cl2CHCOOHCl_2CHCOOH
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2017MCQ· 1mImportance★★★★★
61% · 40/66 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Lactic acid's C-2 carbon carries four different substituents (CH3CH_3, OHOH, COOHCOOH, HH), making it a chiral centre and the molecule optically active.

CH3CH2COOHCH_3CH_2COOH (propanoic acid) has no carbon bonded to four different groups. HOOC−CH2−COOHHOOC-CH_2-COOH (malonic acid) has a CH2CH_2 carbon bonded to two identical HH atoms — not chiral. Cl2CHCOOHCl_2CHCOOH (dichloroacetic acid) has a carbon bearing two identical ClCl atoms — also not chiral. Only CH3CH(OH)COOHCH_3CH(OH)COOH (lactic acid) has a carbon attached to four distinct groups (CH3CH_3, OHOH, COOHCOOH, HH), so it possesses a tru …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.