Skip to content
Question 65 of 67

Q.How many geometrical isomers are possible for [Pt(Py)(NH3)(Br)(Cl)][Pt(Py)(NH_3)(Br)(Cl)] ?

(a) 0
(b) 3
(c) 15
(d) 4
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2026MCQ· 1mImportance★★★★★
97% · 65/67 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

A square planar complex bearing four different unidentate ligands has exactly three ways to arrange them (three choices of which ligand pair ends up directly opposite each other), giving three geometrical isomers.

For a square planar complex of the general type [M(a)(b)(c)(d)][M(a)(b)(c)(d)] — where a,b,c,da, b, c, d are all different unidentate ligands (here: pyridine, NH3NH_3, Br−Br^-, Cl−Cl^-) — the number of possible geometrical isomers depends on which two ligands are placed trans (directly opposite) to each other around the square plane. There are exactly 3 distinct ways to pair up the four ligands into two trans-pairs:

  1. aa trans to bb, and cc trans to dd
  2. aa trans to cc, and bb trans to dd
  3. aa trans to dd, and bb trans to cc …
Start your 14-day free trial to unlock the full solution →

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests
Start 14-day free trial →See Plans & Pricing →

Full access for 14 days. No credit card required.

←Previous questionQ19 — What are hydrate isomers ? Explain with an example.→Next questionQ21 — Give the differences between double salts and coordination compounds.