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Chemistry · Ch 9 — Electrochemistry

First Law

9.6.1

First Law

Faraday's first law of electrolysis states that the mass (m) of a substance liberated or deposited at an electrode during electrolysis is directly proportional to the total quantity of electric charge (Q) passed through the cell:

m∝Qm \propto Q

Since charge relates to current by I=Q/tI = Q/t, so that Q=ItQ = It, this proportionality becomes

m∝Itorm=ZItm \propto It \qquad \text{or} \qquad m = ZIt

where Z is called the electrochemical equivalent of the substance being produced at that electrode. Setting I = 1 A and t = 1 s (so Q = 1 C exactly) reduces the equation to simply m=Zm = Z — which is exactly how the electrochemical equivalent is defined: the mass of substance deposited or liberated at an electrode by exactly one coulomb of charge.

Relating Z to molar mass. For a general reduction Mn+(aq)+ne−→M(s)M^{n+}\text{(aq)} + ne^{-} \rightarrow M\text{(s)}, precipitating one mole of Mn+M^{n+} as metal M requires n moles of electrons, i.e. a charge of nFnF. So the mass deposited by one coulomb of charge — the electrochemical equivalent — works out to

Z=Molar mass of Mn×96500or equivalentlyZ=Equivalent mass96500Z = \dfrac{\text{Molar mass of } M}{n \times 96500} \qquad \text{or equivalently} \qquad Z = \dfrac{\text{Equivalent mass}}{96500} …