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Choose the Best Answer · Q6

Q.Cyclohexylmethanol (cyclohexyl-CH2-OH) on treatment with conc. H2SO4 predominantly gives

a) methylenecyclohexane (an exocyclic C=CH2)
b) 3-methylcyclohex-1-ene (double bond not on the methyl-bearing carbon)
c) 1-methylcyclohex-1-ene (double bond directly on the methyl-bearing carbon)
d) methylcyclohexane (no double bond)
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Step 1. Protonation and loss of water from cyclohexyl-CH2-OH would first generate a PRIMARY carbocation on the exocyclic CH2 -- extremely unstable and never actually formed as such.

Step 2. A 1,2-hydride shift from the adjacent ring carbon into that cationic centre converts the primary cation into a SECONDARY carbocation sitting ON THE RING (at the carbon now bearing a methyl group, since the exocyclic carbon has become CH3 after accepting the hydride). …

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