Skip to content
Question 64 of 70

Q.(a) Derive an expression for Ostwald's Dilution Law. OR

(b)
(i) Why aniline does not undergo Friedel Craft's reaction ?
(ii) How nylon-2-nylon-6 is prepared ?
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2023Subjective· 5mImportance★★★★★
91% · 64/70 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

(a) Ostwald's dilution law derives Ka≈Cα2K_a\approx C\alpha^2 for a weak electrolyte, showing α∝1/C\alpha \propto 1/\sqrt{C} (dissociation rises on dilution). (b) Aniline's lone pair is tied up by AlCl3_3, killing Friedel-Crafts reactivity; nylon-2-nylon-6 is a glycine/6-aminohexanoic-acid copolymer.

(a) Derivation of Ostwald's Dilution Law: Consider a weak, binary electrolyte ABAB ionising in solution: AB⇌A++B−AB \rightleftharpoons A^+ + B^- Let the initial concentration be CC (mol/L) and the degree of dissociation be α\alpha. At equilibrium: [AB]=C(1−α)[AB]=C(1-\alpha), [A+]=Cα[A^+]=C\alpha, [B−]=Cα[B^-]=C\alpha. The dissociation (ionisation) constant is: Ka=[A+][B−][AB]=(Cα)(Cα)C(1−α)=Cα21−αK_a=\frac{[A^+][B^-]}{[AB]}=\frac{(C\alpha)(C\alpha)}{C(1-\alpha)}=\frac{C\alpha^2}{1-\alpha} For a weak electrolyte, α≪1\alpha \ll 1, so (1−α)≈1(1-\alpha)\approx1, giving the approximate form: Ka≈Cα2⇒α≈KaC=KaVK_a \approx C\alpha^2 \quad\Rightarrow\quad \alpha \approx \sqrt{\frac{K_a}{C}}=\sqrt{K_a V} (using C=1/VC=1/V, where VV is the volume containing 1 mole). This is Ostwald's dilution law: since KaK_a is constant at a given temperature, α\alpha increases as CC decreases (i.e. on dilution) — the degree of dissociation of a weak electrolyte increases with dilution.

OR (b)(i) Why aniline does not undergo Friedel-Crafts reaction: Friedel-Crafts alkylation/acylation requires a Lewis acid catalyst, typically anhydrous AlCl3AlCl_3. Aniline's -NH2_2 group carries a lone pair of electrons on nitrogen, which is a good Lewis base; this lone pair immediately reacts with (donates to) the Lewis acid catalyst AlCl3AlCl_3 to form a salt-like complex, C6H5−N+H2−AlCl3−C_6H_5-\overset{+}{N}H_2-AlCl_3^-. Once complexed this way, the nitrogen becomes positively charged, strongly withdrawing electron density from the ring by induction, and the aromatic ring becomes deactivated and effectively meta-directing — the exact opposite of what's needed for electrophilic Friedel-Crafts substitution. Because the required Lewis acid catalyst is consumed/deactivated by the amine itself (rather than activating an electrophile), the Friedel-Crafts reaction fails for aniline.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.