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Choose the Best Answer · Q17

Q.Adsorption of a gas on a solid metal surface is spontaneous and exothermic. Then

(a) ΔH\Delta H increases
(b) ΔS\Delta S increases
(c) ΔG\Delta G increases
(d) ΔS\Delta S decreases
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Step 1. Adsorption is given as spontaneous and exothermic, so ΔG<0\Delta G < 0 and ΔH<0\Delta H < 0 — this already rules out options (a) ΔH\Delta H increases (it decreases/is negative) and (c) ΔG\Delta G increases (it decreases/is negative).

Step 2. When a gas molecule is adsorbed onto a solid surface, it is confined from a comparatively free, mobile gas-phase state into a fixed, ordered position on the surface — this is a decrease in molecular randomness, so ΔS<0\Delta S < 0, i.e. entropy DECREASES. …

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