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Exercise 10.8 · Q4

Q.The engine of a motor boat moving at 10 m/s10\ m/s is shut off. Given that the retardation at any subsequent time (after shutting off the engine) equals the velocity at that time. Find the velocity after 22 seconds of switching off the engine.

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"Retardation equal to velocity" translates to dvdt=−v\dfrac{dv}{dt}=-v; this is exponential decay in vv, fixed by the given initial speed.

Step 1. Set up the model. Retardation is the rate of decrease of speed, and it equals the speed itself: dvdt=−v\dfrac{dv}{dt}=-v.

Step 2. Separate and integrate. dvv=−dt ⟹ ln⁡v=−t+C1 ⟹ v=Ce−t\dfrac{dv}{v}=-dt\ \Longrightarrow\ \ln v=-t+C_1\ \Longrightarrow\ v=Ce^{-t}. …

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