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Exercise 11.1 · Q4

Q.A six-sided die is marked 2' on one face, 3' on two of its faces, and `4' on the remaining three faces. The die is thrown twice. If XX denotes the total score in the two throws, find the values of the random variable and the number of points in its inverse images.

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Since the six faces carry only three distinct values (22 once, 33 twice, 44 thrice), we count ordered face-pairs (not value-pairs) out of 3636, grouping them by the sum they produce.

Step 1. Face counts by value. Value 22: 11 face; value 33: 22 faces; value 44: 33 faces (total 1+2+3=61+2+3=6 faces, consistent).

Step 2. Total sample space size. Two throws of a 66-faced die: ∣S∣=6×6=36|S|=6\times6=36 equally likely face-pairs.

Step 3. List every possible sum and its face-pair count. Writing n2=1,n3=2,n4=3n_2=1,n_3=2,n_4=3 for the face-counts of each value:

X=4X=4 (2+22+2): n2⋅n2=1×1=1n_2\cdot n_2=1\times1=1.

X=5X=5 (2+32+3 or 3+23+2): 2 n2n3=2(1)(2)=42\,n_2n_3=2(1)(2)=4. …

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