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Mathematics · Ch 3 — Theory of Equations

Non-polynomial Equations

3.8.3

Non-polynomial Equations

Some equations aren't polynomial equations at all — yet a well-chosen substitution converts them into one that genuinely is, which can then be solved by every tool above.

Worked illustration (radical equation). 2x+3=x\sqrt{2x+3}=x is not a polynomial equation (the left side has a square root of an xx-dependent quantity). Squaring both sides converts it into the genuine polynomial equation 2x+3=x22x+3=x^2, i.e. x2−2x−3=0=(x−3)(x+1)x^2-2x-3=0=(x-3)(x+1), giving candidates x=3x=3 and x=−1x=-1. Checking back in the original equation: x=3x=3 gives 9=3\sqrt9=3 ✓ (genuine solution), but x=−1x=-1 gives 1=1≠−1\sqrt1=1\ne-1 ✗ — squaring silently flipped the sign requirement, manufacturing an extraneous root that solves the squared (polynomial) equation but not the original one. Every candidate produced this way must be checked back in the original equation before being accepted.

Worked illustration (Example 3.29 — trigonometric, polynomial in cos⁡x\cos x). Solve 2cos⁡2x−9cos⁡x+4=02\cos^2x-9\cos x+4=0. Substituting y=cos⁡xy=\cos x gives the genuine quadratic 2y2−9y+4=02y^2-9y+4=0, with roots y=4y=4 and y=12y=\tfrac12. Now translate back: cos⁡x=4\cos x=4 is never possible (since −1≤cos⁡x≤1-1\le\cos x\le1) and must be discarded; cos⁡x=12\cos x=\tfrac12 has infinitely many solutions, x=2nπ±π3x=2n\pi\pm\tfrac\pi3 for every integer nn.

Watch out

Three honest cautions about this technique, all illustrated above.

  • Not every solution of the derived polynomial equation solves the original one (y=4y=4 above gave no xx at all).
  • A non-polynomial equation dressed up like a polynomial one can have infinitely many solutions (y=12y=\tfrac12 above gave infinitely many xx, unlike a genuine polynomial equation which has finitely many roots). …