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Exercise 3.1 · Q9

Q.If pp and qq are the roots of the equation lx2+nx+n=0lx^2+nx+n=0, show that pq+qp+nl=0\sqrt{\dfrac pq}+\sqrt{\dfrac qp}+\sqrt{\dfrac nl}=0.

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Step 1. Read off Vieta's relations. For lx2+nx+n=0lx^2+nx+n=0: p+q=−nlp+q=-\dfrac nl and pq=nlpq=\dfrac nl.

Step 2. Combine the first two radicals. pq+qp=pq+qp=p+qpq\sqrt{\dfrac pq}+\sqrt{\dfrac qp}=\dfrac{\sqrt p}{\sqrt q}+\dfrac{\sqrt q}{\sqrt p}=\dfrac{p+q}{\sqrt{pq}}.

Step 3. Substitute the Vieta values. =−n/ln/l=−nl=\dfrac{-n/l}{\sqrt{n/l}}=-\sqrt{\dfrac nl} (since cc=c\dfrac{c}{\sqrt c}=\sqrt c for c=n/lc=n/l, with the numerator's sign carried out front). …

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