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Mathematics · Ch 5 — Two Dimensional Analytical Geometry-II

Condition for the Line y = mx + c to be a Tangent to a Conic

5.6.3

Condition for the Line y = mx + c to be a Tangent to a Conic

(i) Parabola y2=4axy^2=4ax. Let y=mx+cy=mx+c be a tangent, touching at (x1,y1)(x_1,y_1). Comparing it with the point-form tangent yy1=2a(x+x1)yy_1=2a(x+x_1) (same line, so coefficients proportional) gives y11=2am=2ax1c\dfrac{y_1}1=\dfrac{2a}m=\dfrac{2ax_1}c, hence y1=2amy_1=\dfrac{2a}m and (substituting into y12=4ax1y_1^2=4ax_1) c=amc=\dfrac am. So

c=am,point of contact (am2,2am),tangent: y=mx+am.\boxed{c=\frac am}, \qquad \text{point of contact } \left(\frac{a}{m^2},\frac{2a}m\right), \qquad \text{tangent: } y=mx+\frac am.

(ii) Ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1. By the same coefficient-matching method, the condition is

c2=a2m2+b2,point of contact (−a2mc,b2c),tangent: y=mx±a2m2+b2.\boxed{c^2=a^2m^2+b^2}, \qquad \text{point of contact } \left(-\frac{a^2m}c,\frac{b^2}c\right), \qquad \text{tangent: } y=mx\pm\sqrt{a^2m^2+b^2}.

(Only one of y=mx+a2m2+b2y=mx+\sqrt{a^2m^2+b^2} or y=mx−a2m2+b2y=mx-\sqrt{a^2m^2+b^2} is the tangent on a given side — not both simultaneously, for the same mm.)

(iii) Hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1. Likewise,

c2=a2m2−b2,point of contact (−a2mc,−b2c),tangent: y=mx±a2m2−b2.\boxed{c^2=a^2m^2-b^2}, \qquad \text{point of contact } \left(-\frac{a^2m}c,-\frac{b^2}c\right), \qquad \text{tangent: } y=mx\pm\sqrt{a^2m^2-b^2}.

Results (proofs left to the reader, exactly as the textbook states them, but stated precisely here for use):

  1. Two tangents can be drawn to a parabola, an ellipse, or a hyperbola from any external point (the slope condition, forced through the external point and squared, is always a quadratic in mm).
  2. Four normals can be drawn to an ellipse or a hyperbola from any external point (the normal-through-a-point condition is a quartic in the parameter). …