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Physics · Ch 2 — Current Electricity

Metre Bridge

2.5.4

Metre Bridge

The metre bridge is simply a practical, laboratory-scale realisation of the Wheatstone's bridge, built around a single one-metre length of uniform manganin wire, AB, stretched along a metre scale on a wooden board between two copper strips, C and D (Figure 2.26). A third copper strip, E, mounted between C and D, splits the bridge wire's two gaps: an unknown resistance P is connected in gap G1G_1, and a known, standard resistance Q is connected in gap G2G_2. A jockey (a sliding contact) connected to strip E through a galvanometer G and a high resistance HR can be moved along the wire, its exact position read off directly against the metre scale; a Lechlanche cell and a key K complete the primary circuit across the two ends of the bridge wire.

The jockey's position is adjusted until the galvanometer shows exactly zero deflection, at position J on the wire. At this balance point, the portions of bridge wire AJ (length l1l_1) and JB (length l2l_2) act as the bridge's R and S arms (since resistance is proportional to length for a uniform wire of resistance-per-length r), so the balance condition P/Q=R/SP/Q=R/S from equation (2.53) becomes

PQ=r⋅l1r⋅l2=l1l2(2.54, 2.55, 2.56)\dfrac{P}{Q} = \dfrac{r\cdot l_1}{r\cdot l_2} = \dfrac{l_1}{l_2} \qquad (2.54,\ 2.55,\ 2.56) …

Figure 2.26Metre bridge

What this figure shows. A one-metre manganin wire AB is stretched along a metre scale on a wooden board between two copper strips C and D; a third copper strip E sits between them, splitting the setup into two gaps, G1G_1 (holding the unknown resistance P) and G2G_2 (holding the standard resistance Q). A jockey J, connected through a galvanometer G and a high resistance HR, can slide along the wire; a Lechlanche cell and key K complete the primary circuit across the ends of the bridge wire. The jockey's null-deflection position …

Misc Example 2.25Unknown resistance from a given balancing-length ratio

Worked out. In a metre bridge experiment with a standard resistance Q=15 ΩQ=15\ \Omega in the right gap, the balancing lengths come out in the ratio l1:l2=3:2l_1:l_2=3:2; the unknown resistance P is required. Using P/Q=l1/l2P/Q=l_1/l_2: P=Q×(l1/l2)=15×(3/2)=22.5 ΩP=Q\times(l_1/l_2)=15\times(3/2)=22.5\ \Omega. …

Misc Example 2.26Unknown resistance from a measured balancing length

Worked out. In a metre bridge experiment, the standard resistance in the right gap is Q=10 ΩQ=10\ \Omega and the balancing length is l1=55l_1=55 cm (so l2=100−55=45l_2=100-55=45 cm); the unknown resistance P is required. Using P/Q=l1/l2P/Q=l_1/l_2: P=Q×(l1/l2)=10×(55/45)=550/45≈12.2 ΩP=Q\times(l_1/l_2)=10\times(55/45)=550/45\approx12.2\ \Omega. …