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Physics · Ch 2 — Current Electricity

Ohm's Law

2.2

Ohm's Law

Starting directly from the microscopic form of Ohm's law, J=σEJ = \sigma E, consider a uniform segment of wire of length l and cross-sectional area A. Assuming the electric field is uniform along the wire's length, the potential difference (voltage) across it can be written V=ElV = El, i.e. E=V/lE = V/l. Also, since J=I/AJ = I/A, substituting both into J=σEJ=\sigma E gives IA=σVl\dfrac{I}{A} = \sigma\dfrac{V}{l} (2.14), which rearranges to

V=I(lσA)(2.15)V = I\left(\dfrac{l}{\sigma A}\right) \qquad (2.15)

The quantity l/(σA)l/(\sigma A) depends only on the conductor's geometry (its length and area) and material (through σ\sigma), and is defined as the resistance R of the conductor. This turns equation (2.15) into the everyday, macroscopic form of Ohm's law:

V=IR(2.16)V = IR \qquad (2.16) …

Figure 2.7Current through the conductor

What this figure shows. A straight cylindrical wire of length l and cross-sectional area A is shown with an electric field arrow E drawn along its axis, current I flowing through it, and the potential difference V marked across its two ends -- the exact geometric setup used to turn the microscopic relation J=σEJ = \sigma E into the macr …

Figure 2.8Current against voltage for an ohmic and a non-ohmic device

What this figure shows. Two side-by-side I-versus-V graphs. Graph (a) shows a straight line passing through the origin, with its slope explicitly labelled as 1/R1/R -- this is the signature of an ohmic material, whose resistance R stays constant regardless of the applied voltage. Graph (b) shows a curved, non-linear line (also starting near the origin) for a non-ohmic device such as a diode (covered later in Unit 9): because this curve's slope keeps changing, such a device has no single, consta …

Misc Example 2.5Current through a resistor from Ohm's law

Worked out. A potential difference of 12 V is applied across a 24 Ω24\ \Omega resistor, and the current through it is required. Direct application of Ohm's law, I=V/R=12/24=0.5I = V/R = 12/24 = 0.5 A. This is the simplest possible one-step use of the macroscopic form of Ohm's law. …