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Physics · Ch 2 — Current Electricity

Microscopic Model of Current

2.1.3

Microscopic Model of Current

Building the current formula from first principles: consider a conductor of cross-sectional area A with an electric field E⃗\vec E applied along it, containing n free electrons per unit volume, all assumed to move with the same drift velocity vdv_d. If an electron moves through a small distance dx in a small time interval dt, then vd=dx/dtv_d = dx/dt, so dx=vd dtdx = v_d\,dt (2.7). The number of electrons contained in this thin slice of the conductor, of length dx and cross-sectional area A, is the slice's volume times the electron number density: A dx⋅nA\,dx\cdot n (2.8). Substituting dx=vd dtdx = v_d\,dt from (2.7) into (2.8), the number of electrons in the slice becomes (A vd dt) n(A\,v_d\,dt)\,n, and since each electron carries charge e, the total charge in this volume element is

dQ=e (A vd dt) ndQ = e\,(A\,v_d\,dt)\,n

Hence the current, I=dQ/dtI = dQ/dt, works out to

I=ne A vd(2.9)I = ne\,A\,v_d \qquad (2.9)

This is the central microscopic-model result: current is directly proportional to the electron number density, the electron's charge, the conductor's cross-sectional area, and the drift velocity.

Current density (J) is defined as the current per unit cross-sectional area, J=I/AJ = I/A, with SI unit A/m2\text{A/m}^2. Substituting equation (2.9) gives J=ne vdJ = ne\,v_d (2.10) -- a relation that holds exactly when current flows perpendicular to A. In general, current density is treated as a vector quantity (its direction is the direction positive charge is actually flowing at a point), written J⃗=ne v⃗d\vec J = ne\,\vec v_d. Substituting the drift-velocity expression v⃗d=−(eτ/m)E⃗\vec v_d = -(e\tau/m)\vec E from equation (2.4) gives

J⃗=−ne2τmE⃗(2.11)\vec J = -\dfrac{ne^2\tau}{m}\vec E \qquad (2.11)

Since by convention the direction of conventional current density is taken along E⃗\vec E (not opposite to it, as the raw electron-based derivation would suggest, because the flowing charge carriers are actually negative), this is written as

J⃗=σE⃗(2.12)\vec J = \sigma \vec E \qquad (2.12) …

Figure 2.5Microscopic model of current

What this figure shows. A conductor of cross-sectional area A is drawn with an electric field E⃗\vec E applied along it and several electron symbols (with drift velocity vdv_d) shown inside a thin slice of thickness dxdx marked off within the conductor; the slice's volume, multiplied by the number density n of free electrons, is used to count exactly how many electrons cross the area A in the small time interval dt -- the core geo …

Misc Example 2.3Drift velocity from current and electron density

Worked out. A copper wire of cross-sectional area 0.5 mm20.5\ \text{mm}^2 carries a current of 0.2 A, and the free-electron density of copper is given as 8.4×1028 m−38.4\times10^{28}\ \text{m}^{-3}; the drift velocity is required. Rearranging I=neAvdI = neAv_d gives vd=I/(neA)v_d = I/(neA). Substituting I=0.2I = 0.2 A, n=8.4×1028 m−3n = 8.4\times10^{28}\ \text{m}^{-3}, e=1.6×10−19e = 1.6\times10^{-19} C and A=0.5×10−6 m2A = 0.5\times10^{-6}\ \text{m}^2 gives vd≈0.03×10−3 m/sv_d \approx 0.03\times10^{-3}\ \text{m/s}, i.e. only about 3×10−53\times10^{-5} m/s. This tiny value -- a few centimetres per hour -- is the standard illustration of just how slowly electrons actually drift even wh …

Misc Example 2.4Number of electrons flowing per second

Worked out. The question asks how many electrons flow per second through a conductor carrying a current of 32 A. Since I=Q/t=ne/tI = Q/t = ne/t for t=1t = 1 s, rearranging gives n=It/en = It/e. Substituting I=32I = 32 A, t=1t = 1 s and e=1.6×10−19e = 1.6\times10^{-19} C gives n=32/(1.6×10−19)=20×1019=2×1020n = 32/(1.6\times10^{-19}) = 20\times10^{19} = 2\times10^{20} electrons per second. This huge number of electrons crossing any cross-section every second is exactly why even a modest current corresponds to a very large charge flow, despite each individual electr …

Misc ~note-scalar-vectorWhy current density is a vector but current is a scalar

Worked out. This aside resolves an apparent puzzle: current density J⃗\vec J is defined as a vector (it points in the direction of positive charge flow at a point), yet the total current I through a surface is a scalar. The resolution is that I is defined as the scalar (dot) product of the current density vector and the area vector through which the charges cross, I=J⃗⋅A⃗=JAcos⁡θI = \vec J \cdot \vec A = JA\cos\theta, where θ\theta is the angle between J⃗\vec J and the outward normal to the surface. Because I is built from a dot product of two vectors, it comes out as a single number (which can even be positive or negative depending on which way the area's normal vector is chosen), even though the current density feeding into it is genuinely a ve …