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IV. Numerical Problems · Q2

Q.A transmitter consists of an LC circuit with an inductance of 1 μ\muH and a capacitance of 1 μ\muF. What is the wavelength of the electromagnetic waves it emits?

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✓ Free question

Step 1. An LC circuit oscillates at its natural (resonant) frequency f=12πLCf=\dfrac{1}{2\pi\sqrt{LC}}, with L=1 μH=1×10−6L=1\ \mu\text{H}=1\times10^{-6} H and C=1 μF=1×10−6C=1\ \mu\text{F}=1\times10^{-6} F.

Step 2. LC=(10−6)(10−6)=10−12=10−6\sqrt{LC}=\sqrt{(10^{-6})(10^{-6})}=\sqrt{10^{-12}}=10^{-6} s.

Step 3. f=12π×10−6≈16.283×10−6≈1.5915×105f=\dfrac{1}{2\pi\times10^{-6}}\approx\dfrac{1}{6.283\times10^{-6}}\approx1.5915\times10^5 Hz.

Step 4. The oscillating current in this LC circuit is an accelerating charge, so it radiates an electromagnetic wave at exactly this frequency; its wavelength is λ=c/f=3×1081.5915×105≈1884.96\lambda=c/f=\dfrac{3\times10^8}{1.5915\times10^5}\approx1884.96 m ≈18.84×102\approx18.84\times10^2 m, matching the book's given answer.

✓Final answer

λ≈18.84×102\lambda\approx18.84\times10^2 m

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