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Q.Discuss the action of a Bainbridge mass spectrometer to determine the isotopic masses.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2018Subjective· 10mImportance★★★★★
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The Bainbridge mass spectrometer combines a velocity selector (crossed electric and magnetic fields) with a separate uniform magnetic-field region; ions of a given charge and velocity trace semicircular paths whose radius depends only on their mass, letting isotopic masses be measured very precisely.

Construction

The apparatus has three main parts: (i) an ion source that produces positive ions of the element/isotopes to be studied (usually by ionising a vapour and accelerating the ions through a potential difference);

(ii) a velocity selector, a region with a uniform electric field E⃗\vec E and a uniform magnetic field B⃗1\vec B_1 arranged perpendicular to each other and to the ion's initial velocity;

(iii) a separate deflecting chamber with a uniform magnetic field B⃗2\vec B_2, with a photographic plate or detector at the far end.

Working

Step 1 — Velocity selection: The ions, of charge qq, enter the velocity selector, where they experience an electric force qEqE and a magnetic force qvB1qvB_1 (from v⃗×B⃗1\vec v \times \vec B_1). Only ions moving with the particular speed for which these two forces exactly balance travel straight through the narrow exit slit; all others are deflected and blocked. The balance condition is

qE=qvB1  ⇒  v=EB1qE = qvB_1 \;\Rightarrow\; v = \dfrac{E}{B_1}

Thus every ion that emerges from the selector — regardless of its mass — has the same known speed vv.

Step 2 — Circular deflection: These selected ions then enter the second region, where only the uniform magnetic field B2B_2 acts (perpendicular to v⃗\vec v). The magnetic force provides the centripetal force for circular motion:

qvB2=mv2r  ⇒  r=mvqB2qvB_2 = \dfrac{mv^2}{r} \;\Rightarrow\; r = \dfrac{mv}{qB_2}

The ion travels a semicircular path of radius rr and strikes a photographic plate at a distance 2r2r from the entry slit.

Step 3 — Determining the mass: Since v=E/B1v = E/B_1, substituting gives

r=mqB2⋅EB1  ⇒  m=qB1B2rEr = \dfrac{m}{qB_2}\cdot\dfrac{E}{B_1} \;\Rightarrow\; m = \dfrac{qB_1B_2 r}{E}

All quantities on the right (qq, B1B_1, B2B_2, EE) are known/set by the apparatus, and rr is measured from the position of the trace on the photographic plate. Hence the mass mm of each isotope can be calculated very precisely.

Determining isotopic masses …

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