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Evaluation · Q12

Q.Father of a child is colourblind and mother is carrier for colourblindness, the probability of the child being colourblind is

(a) 25%
(b) 50%
(c) 100%
(d) 75%
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
18% · 12/68 Questions
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Step 1. Write the parental genotypes: colourblind father = XcY (hemizygous recessive); carrier mother = XCXc (heterozygous, normal vision but carrying the recessive allele).

Step 2. List the gametes: father gives Xc or Y; mother gives XC or Xc.

Step 3. Cross all four combinations: XC(mother) x Xc(father) → XCXc, carrier daughter, normal vision; Xc(mother) x Xc(father) → XcXc, colourblind daughter; XC(mother) x Y(father) → XCY, normal son; Xc(mother) x Y(father) → XcY, colourblind son. …

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