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Q.Explain the hybridization involved in SF6 molecule.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2023Subjective· 4mImportance★★★★★
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Sulphur in SF6 uses sp3d2 hybridisation to form six equivalent orbitals pointing to the corners of an octahedron, giving an octahedral SF6 molecule.

SF6 - hybridisation of sulphur:

Step 1 - Ground-state configuration of sulphur:

S (Z = 16): [Ne] 3s2 3p4 (only two unpaired electrons).

Step 2 - Excited state:

Sulphur has vacant 3d orbitals. To form six bonds, one 3s electron and one 3p electron are promoted into two of the 3d orbitals, giving six unpaired electrons (one 3s + three 3p + two 3d, each singly occupied).

Step 3 - Hybridisation:

These six orbitals (one s + three p + two d) mix to form six equivalent sp3d2 hybrid orbitals.

Step 4 - Geometry: …

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