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Exercises · 9.21

Q.W rite structures of all the alkenes which on hydrogenation give 2-methylbutane.

Telangana TsbieTextbookSubjective· 2mImportance★★★★★est
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Hydrogenation only removes the C=C and leaves the carbon skeleton unchanged, so we insert a double bond at each distinct position of the 2-methylbutane skeleton. Three alkenes result: 2-methylbut-1-ene, 2-methylbut-2-ene and 3-methylbut-1-ene.

Working back from the product

2-Methylbutane is (CH3)2CH−CH2−CH3(CH_3)_2CH-CH_2-CH_3. Placing a C=C at each distinct bond of this skeleton:

  • C1-C2: CH2=C(CH3)−CH2−CH3CH_2=C(CH_3)-CH_2-CH_3 gives 2-methylbut-1-ene
  • C2-C3: (CH3)2C=CH−CH3(CH_3)_2C=CH-CH_3 gives 2-methylbut-2-ene
  • C3-C4: (CH3)2CH−CH=CH2(CH_3)_2CH-CH=CH_2 gives 3-methylbut-1-ene …

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