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Exercises · 11.37

Q.Elements of group 14

(a) exhibit oxidation state of +4 only
(b) exhibit oxidation state of +2 and +4
(c) form M2– and M4+ ions
(d) form M2+ and M4+ ions
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Group 14 elements show the group-typical +4 state, but the inert pair effect increasingly stabilises +2 down the group, so both +2 and +4 states are exhibited — never simple M2−^{2-}/M4+^{4+} ionic extremes.

  1. The group-typical +4 state. With the outer configuration ns2np2ns^2np^2, all four valence electrons of a Group 14 element can in principle participate in covalent bonding, giving compounds in the +4 oxidation state (e.g. CCl4_4, SiCl4_4, SnCl4_4, PbCl4_4) — this is the state expected purely from the group number.
  2. The +2 state and the inert pair effect. Going down the group, the inert pair effect (the ns2ns^2 pair's increasing reluctance to participate in bonding) makes the +2 oxidation state progressively more important: it is negligible for carbon and silicon, becomes significant for germanium, is common for tin (SnCl2_2 and SnCl4_4 both well known), and for lead the +2 state (Pb2+^{2+}, e.g. in PbO, PbCl2_2) is actually more stable than +4. …

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